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	<title>GCE &#34;A&#34; Level Cambridge Chemistry: Small-sized Focus Tuition</title>
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	<description>Updates on &#34;A&#34; level H2 Chemistry / Group tuition in Singapore</description>
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		<title>GCE &#34;A&#34; Level Cambridge Chemistry: Small-sized Focus Tuition</title>
		<link>http://cambridgechemistry.wordpress.com</link>
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		<title>A Chemical Volcano: The Decomposition of Ammonium Dichromate</title>
		<link>http://cambridgechemistry.wordpress.com/2009/09/22/a-chemical-volcano-the-decomposition-of-ammonium-dichromate/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/09/22/a-chemical-volcano-the-decomposition-of-ammonium-dichromate/#comments</comments>
		<pubDate>Tue, 22 Sep 2009 15:17:33 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Chemical Energetics]]></category>
		<category><![CDATA[Decomposition]]></category>
		<category><![CDATA[Volcano]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=140</guid>
		<description><![CDATA[This question was asked for a Secondary 4 prelim paper, which I find it interesting to share with all Chemistry students.
The making of a mini-volcano.
Did you know that ammonium dichromate, (NH4)2Cr2O7 when exposed to heat, will decompose to form Nitrogen gas, Water Vapor and a green compound Chromium III oxide, Cr2O3.
This reaction is highly exothermic, [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=140&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>This question was asked for a Secondary 4 prelim paper, which I find it interesting to share with all Chemistry students.</p>
<p>The making of a mini-volcano.</p>
<p>Did you know that ammonium dichromate, <strong>(NH4)2Cr2O7</strong> when exposed to heat, will decompose to form Nitrogen gas, Water Vapor and a green compound Chromium III oxide, Cr2O3.</p>
<p>This reaction is highly exothermic, and gives off orange sparks, throws the green Cr2O3 upwards, mimicking the volcanic-effect.</p>
<p><strong>!!!  Hazards  !!! DO NOT TRY THIS AT HOME. </strong>Ammonium Dichromate causes cancer!</p>
<p>Chromium salts are irritating to the skin and respiratory tracts, and are also carcinogenic.    The best way to do this demonstration is on a large piece of aluminum foil, which can then be used to wrap up the chromium salts produced.</p>
<p><strong>Videos to watch:</strong></p>
<p><span style="text-align:center; display: block;"><a href="http://cambridgechemistry.wordpress.com/2009/09/22/a-chemical-volcano-the-decomposition-of-ammonium-dichromate/"><img src="http://img.youtube.com/vi/Fy4LLdhjsb8/2.jpg" alt="" /></a></span></p>
<p><span style="text-align:center; display: block;"><a href="http://cambridgechemistry.wordpress.com/2009/09/22/a-chemical-volcano-the-decomposition-of-ammonium-dichromate/"><img src="http://img.youtube.com/vi/Ula2NWi3Q34/2.jpg" alt="" /></a></span></p>
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		<title>What is fractional distillation of petrols?</title>
		<link>http://cambridgechemistry.wordpress.com/2009/08/22/what-is-fractional-distillation-of-petrols/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/08/22/what-is-fractional-distillation-of-petrols/#comments</comments>
		<pubDate>Sat, 22 Aug 2009 15:21:15 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Organic Chemistry]]></category>
		<category><![CDATA[fractional distillation]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=143</guid>
		<description><![CDATA[A very good video (1min 30 sec) to explain how crude oil is separated into its separate fractions by fractional distillation.

       <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=143&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>A very good video (1min 30 sec) to explain how crude oil is separated into its separate fractions by fractional distillation.</p>
<p><span style="text-align:center; display: block;"><a href="http://cambridgechemistry.wordpress.com/2009/08/22/what-is-fractional-distillation-of-petrols/"><img src="http://img.youtube.com/vi/26AN1LfbUPc/2.jpg" alt="" /></a></span></p>
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		<title>Reflux Conditions</title>
		<link>http://cambridgechemistry.wordpress.com/2009/07/22/reflux-conditions/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/07/22/reflux-conditions/#comments</comments>
		<pubDate>Wed, 22 Jul 2009 15:25:34 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Chemical Kinetics]]></category>
		<category><![CDATA[Organic Chemistry]]></category>
		<category><![CDATA[Experimental techniques]]></category>
		<category><![CDATA[reflux]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=145</guid>
		<description><![CDATA[Many students wonder what &#8220;heat under reflux&#8221; is like in the laboratory.
It is something like distillation but it is performed for long hours, sometimes overnight to ensure all the reactants are thoroughly boiled.
Watch this short video to have an idea of what reflux conditions are like &#8212; and you will understand why reflux are often [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=145&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Many students wonder what &#8220;<strong>heat under reflux</strong>&#8221; is like in the laboratory.</p>
<p>It is something like distillation but it is performed for long hours, sometimes overnight to ensure all the reactants are thoroughly boiled.</p>
<p>Watch this short video to have an idea of what reflux conditions are like &#8212; and you will understand why reflux are often considered drastic conditions.</p>
<p>A detailed demonstration (2min):<br />
<span style="text-align:center; display: block;"><a href="http://cambridgechemistry.wordpress.com/2009/07/22/reflux-conditions/"><img src="http://img.youtube.com/vi/3diTdagF-6U/2.jpg" alt="" /></a></span></p>
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		<title>Question of Chemical Equilibria</title>
		<link>http://cambridgechemistry.wordpress.com/2009/05/15/question-of-chemical-equilibria/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/05/15/question-of-chemical-equilibria/#comments</comments>
		<pubDate>Thu, 14 May 2009 16:34:31 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Chemical Equilibrium]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=113</guid>
		<description><![CDATA[Pure hydrogen iodide (HI) is a gas, which at high temperatures, partially dissociates into hydrogen and iodine according to the equation:
2HI (g) &#60; &#8212;- &#62; H2(g) + I2(g)
At 500K, the equilibrium constant, Kc, for the dissociation reaction is 6.25 x 10^-3.  Some pure HI is placed into an evacuated 2.0 dm3 glass tube and heated [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=113&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Pure hydrogen iodide (HI) is a gas, which at high temperatures, partially dissociates into hydrogen and iodine according to the equation:</p>
<p><strong>2HI (g) &lt; &#8212;- &gt; H2(g) + I2(g)</strong></p>
<p>At 500K, the equilibrium constant, Kc, for the dissociation reaction is <span style="text-decoration:underline;">6.25 x 10^-3</span>.  Some pure HI is placed into an evacuated 2.0 dm3 glass tube and heated to 500K. In the equilibrium sample, the concentration of I2 is 3.10 x 10^-5 moldm^-3.</p>
<p>ai) Write an <strong>expression for the Kc </strong>for the dissociation of HI.<br />
ii) What are the <strong>concentrations of H2(g) and HI(g)</strong> in this equilibrium mixture at 500K?<br />
iii) How many<strong> moles of HI  must have been placed</strong> into the 2.0dm3 glass tube originally?</p>
<p>b) At 600K, Kc for the dissociation of HI is 1.56&#215;10^-2. <strong>Describe and explain </strong>the appearance of the contents in this glass as it is heated to 600K.</p>
<p>c) Hydrogen chloride at 500K undergoes no significant dissociation into its elements. Any dissociation of hydrogen chloride can be completely ignored. <strong>What is the pressure in a 750cm3 flask</strong> containing <span style="text-decoration:underline;">8.20 x 10^-2</span> mol of pure HCl at 500K?<br />
<span style="color:#0000ff;"><em><br />
<span style="color:#ff00ff;"><strong>Once you have the answers, you can post it here or email me at cambridgechemistry(NOSPAM)@yahoo.com.sg </strong></span></em></span></p>
<p><span style="color:#ff00ff;"><strong><em>Enjoy!</em></strong></span></p>
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		<title>Question on Thermochemistry</title>
		<link>http://cambridgechemistry.wordpress.com/2009/05/12/question-on-thermochemistry/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/05/12/question-on-thermochemistry/#comments</comments>
		<pubDate>Mon, 11 May 2009 16:31:36 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Chemical Energetics]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=110</guid>
		<description><![CDATA[a) Using zinc chloride, ZnCl2, as an example, define lattice energy.
b) Using the data given below as well as relevant data from the Data Booklet, construct a Born-Haber energy level diagram for zinc chloride.
Electron affinity of chlorine = -346 kJmol-1
Enthalpy change of atomization of zinc = +131 kJmol-1
Enthalpy change of formation of ZnCl2(s) = -451 [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=110&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>a) Using zinc chloride, ZnCl2, as an example, <strong>define lattice energy</strong>.</p>
<p>b) Using the data given below as well as relevant data from the Data Booklet, <strong>construct a Born-Haber energy level diagram for zinc chloride.</strong><br />
Electron affinity of chlorine = -346 kJmol-1<br />
Enthalpy change of atomization of zinc = +131 kJmol-1<br />
Enthalpy change of formation of ZnCl2(s) = -451 kJmol-1</p>
<p>Use the energy level diagram to <strong>calculate the lattice energy of zinc chloride</strong></p>
<p>c) How would you expect the melting point of zinc chloride to <span style="text-decoration:underline;">compare</span> with that of zinc bromide?<br />
Explain your reasoning.</p>
<p><span style="color:#000080;"><em>If you have the answer, you can post or email me at cambridgechemistry(NOSPAM)@yahoo.com.sg</em></span></p>
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		<title>Mole concept &#8211; for the Year Ones</title>
		<link>http://cambridgechemistry.wordpress.com/2009/03/23/mole-concept-for-the-year-ones/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/03/23/mole-concept-for-the-year-ones/#comments</comments>
		<pubDate>Sun, 22 Mar 2009 18:39:11 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[Today I started a JC 1 class revising secondary 4 work on mole concept and calculations.
For the stronger Chemistry students, this chapter might seem easy to handle, which is a good thing. However, do not be complacent, and always be alert with calculations.
It is easy to make careless mistakes and overlook the number of  zeroes [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=100&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Today I started a JC 1 class revising secondary 4 work on mole concept and calculations.</p>
<p>For the stronger Chemistry students, this chapter might seem easy to handle, which is a good thing. However, do not be complacent, and always be alert with calculations.</p>
<p>It is easy to make careless mistakes and overlook the number of  zeroes and decimal place.</p>
<p>Also, the mole reacting ratio can be rather challenging at times.</p>
<p>If you need further help ,please feel free to post a comment here for all to learn or email me at <span style="color:#ff00ff;"><span style="text-decoration:underline;"><strong>cambridgechemistry[at]yahoo[dot]com[dot]sg</strong></span></span></p>
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		<title>Merry Xmas and a&#8230;..</title>
		<link>http://cambridgechemistry.wordpress.com/2008/12/14/merry-xmas-and-a/</link>
		<comments>http://cambridgechemistry.wordpress.com/2008/12/14/merry-xmas-and-a/#comments</comments>
		<pubDate>Sun, 14 Dec 2008 13:41:08 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[&#8216;Tis the season to be jolly, falalalalalala..
MERRY CHRISTMAS BOYS AND GIRLS  
To those who have graduated, congratulations! You have made it!
For those embarking the journey in Chemistry or in the midst, hope you are enjoying the journey thus far, or at least have a better appreciation of Chemistry.
It is always good to start early, [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=86&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>&#8216;Tis the season to be jolly, falalalalalala..<br />
MERRY CHRISTMAS BOYS AND GIRLS <img src='http://s.wordpress.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
<p>To those who have graduated, congratulations! You have made it!</p>
<p>For those embarking the journey in Chemistry or in the midst, hope you are enjoying the journey thus far, or at least have a better appreciation of Chemistry.</p>
<p>It is always good to start early, so remember to START DOING YOUR SCHOOL HOLIDAY HOMEWORK! hahaha.</p>
<p>Let me know if you need any clarification or assistance.</p>
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		<title>Titration between acids / bases</title>
		<link>http://cambridgechemistry.wordpress.com/2008/10/30/titration-between-acids-bases/</link>
		<comments>http://cambridgechemistry.wordpress.com/2008/10/30/titration-between-acids-bases/#comments</comments>
		<pubDate>Wed, 29 Oct 2008 21:31:09 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Ionic Equilibrium]]></category>

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		<description><![CDATA[Equivalence point or end-point (when equivalence volume is added such that no more acids nor bases are left, only left with salt)
SALT can be classified as
1) NEUTRAL (usually between strong acids and strong bases. pH = 7, due to hydration only)
2) ACIDIC (usually between strong acids and weak bases. pH &#60; 7 due to conjugate [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=66&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Equivalence point or end-point (when equivalence volume is added such that no more acids nor bases are left, only left with salt)</p>
<p>SALT can be classified as<br />
1) NEUTRAL (usually between strong acids and strong bases. pH = 7, due to hydration only)<br />
2) ACIDIC (usually between strong acids and weak bases. pH &lt; 7 due to conjugate acid of weak base)<br />
3) BASIC  (usually between weak acids and strong bases. pH &gt; 7 due to conjugate base of weak acid) </p>
<p>If a base is weak, i.e. undergoes partial ionisation; then its conjugate acid also undergoes partial ionisation. Therefore, a weak base has its own Kb value, and thus its conjugate acid will have its own Ka value ( where Ka = Kw/Kb)</p>
<p>Reverse is true for weak acids and its conjugate bases.</p>
<p>In general, for any substance that behaves as a weak acid (recall, Lowry-Brosted theory states that acid donates H+), to calculate pH, <br />
- [H+] = sq. root (Ka.[acid])<br />
-pH = -lg [H+]</p>
<p>In general, for any substance that behaves as a weak base (recall, Lowry-Brosted theory states that base accepts H+), to calculate pH, <br />
- [OH-] = sq. root (Kb.[base])<br />
-pOH = -lg [OH-]<br />
-pH = 14 &#8211; pOH</p>
<p>Thus a salt can behave as a weak acid or a weak base depending on whether it can accepts or donates H+</p>
<p>Hope this helps !</p>
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		<title>Organic tips</title>
		<link>http://cambridgechemistry.wordpress.com/2008/10/30/organic-tips/</link>
		<comments>http://cambridgechemistry.wordpress.com/2008/10/30/organic-tips/#comments</comments>
		<pubDate>Wed, 29 Oct 2008 21:23:20 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Aromatic Compounds]]></category>
		<category><![CDATA[Mechanisms]]></category>

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		<description><![CDATA[Just a quick tip: 
This is for the electrophilic substitution/ bromination for Phenols and Phenylamines.
1) Br2 (g) in CCl4 &#8212;-&#62; mono-substituted phenol/phenylamine
2) Br2 (l)              &#8212;&#8211;&#62; di-substituted phenol/phenylamine
3) Br2 (ag)           &#8212;&#8212;&#62; tri-substituted phenol/phenylamine
Another quick revision tip:
Metal-acid reaction is also a reduction/oxidation process
Please remember that in Nucleophilic [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=64&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Just a quick tip: </p>
<p>This is for the electrophilic substitution/ bromination for Phenols and Phenylamines.</p>
<p>1) Br2 (g) in CCl4 &#8212;-&gt; mono-substituted phenol/phenylamine<br />
2) Br2 (l)              &#8212;&#8211;&gt; di-substituted phenol/phenylamine<br />
3) Br2 (ag)           &#8212;&#8212;&gt; tri-substituted phenol/phenylamine</p>
<p>Another quick revision tip:</p>
<p>Metal-acid reaction is also a reduction/oxidation process</p>
<p>Please remember that in Nucleophilic addition, a racemic mixture is most likely to be formed, unless the reaction is performed naturally by enzymes in living organisms</p>
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		<title>Quick Revision Test for Ionic Equilibria</title>
		<link>http://cambridgechemistry.wordpress.com/2008/10/21/quick-revision-test-for-ionic-equilibria/</link>
		<comments>http://cambridgechemistry.wordpress.com/2008/10/21/quick-revision-test-for-ionic-equilibria/#comments</comments>
		<pubDate>Mon, 20 Oct 2008 16:47:35 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Ionic Equilibrium]]></category>

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		<description><![CDATA[Question: Methylamine, CH3NH2, is a weak base with pKb value of 3.36 in water.
15.00cm3 of 0.500moldm-3 of methylamine solution was titrated against 0.30moldm-3 of aqueous hydrochloric acid. Sketch the acid-base titration graph.
       <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&blog=4089614&post=62&subd=cambridgechemistry&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p><em>Question: Methylamine, CH</em><sub><em>3</em></sub><em>NH</em><sub><em>2</em></sub><em>, is a weak base with pK</em><sub><em>b</em></sub><em> value of 3.36 in water.<br />
15.00cm</em><sup><em>3</em></sup><em> of 0.500moldm</em><sup><em>-3</em></sup><em> of methylamine solution was titrated against 0.30moldm</em><sup><em>-3</em></sup><em> of aqueous hydrochloric acid.</em><span><em> </em></span><em>Sketch the acid-base titration </em><strong><em>graph.</em></strong></p>
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