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	<title>GCE &#34;A&#34; Level Cambridge Chemistry: Small-sized Focus Tuition</title>
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		<title>GCE &#34;A&#34; Level Cambridge Chemistry: Small-sized Focus Tuition</title>
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		<title>8th year of teaching&#8230;.</title>
		<link>http://cambridgechemistry.wordpress.com/2010/06/23/8th-year-of-teaching/</link>
		<comments>http://cambridgechemistry.wordpress.com/2010/06/23/8th-year-of-teaching/#comments</comments>
		<pubDate>Tue, 22 Jun 2010 20:23:34 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=158</guid>
		<description><![CDATA[It has been 8 years of me doing private tutoring and coaching for students from most JCs..wow time flies, and I still feel young and the memory of the JC life is still vivid in my mind. I remembered when I was a JC student in 2001, going through Chemistry lesson was rather tedious for [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=158&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>It has been 8 years of me doing private tutoring and coaching for students from most JCs..wow time flies, and I still feel young and the memory of the JC life is still vivid in my mind.</p>
<p>I remembered when I was a JC student in 2001, going through Chemistry lesson was rather tedious for me. FIrst chapter, BOOM&#8230;redox and mole concept suddenly became &#8220;so difficult&#8221; for me, incomprehensible.</p>
<p>I thought to myself: what kind of mole concept is this that I do not know how to answer? I thought I have understood it since O level.</p>
<p>Chemistry was not really my number one favorite and strong subject since Secondary/Junior High, so it&#8217;s rather strange that now I find myself teaching Chemistry.</p>
<p>I have always preferred Biology, as it makes more sense, probably because I can relate the subject to our everyday life better?</p>
<p>I always like to make sense of things when I am learning or doing things. The art and skill of making sense of things does not come overnight, I feel. It really comes with a KEEN SENSE OF OBSERVATION and A VERY OPEN MIND IN EXPANDING WHAT YOU ALREADY KNOW.</p>
<p>The human mind has the tendency to want to stay within the &#8220;comfort&#8221; zone, so in order to excel in whatever you do, always CHALLENGE.</p>
<p>Honestly, there is no such thing as &#8220;wrong&#8221;, what is wrong determined by the definition of the public mass.</p>
<p>Science is the study of things, so essentially, we are living Science everyday even though you do not realize it!</p>
<p>This is how I try to inculcate students the mentality towards approaching learning Chemistry. Of course, I will get down to the books if you really cannot understand.</p>
<p>After all, I am really good at summarizing essential things for you- all you need to do is really to remember all the essential things!</p>
<p>&#8220;A&#8221; levels is 4 months away:- better to start early than late.  4 months is a good enough time to prep your grades up from F to A, as long as you possess the above skills as mentioned, and SINCERELY want to learn and to do well.</p>
<p><strong><span style="color:#00ccff;">P.S. If you need FREE online teaching, please leave your comments here.<br />
</span></strong></p>
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		<title>A Chemical Volcano: The Decomposition of Ammonium Dichromate</title>
		<link>http://cambridgechemistry.wordpress.com/2009/09/22/a-chemical-volcano-the-decomposition-of-ammonium-dichromate/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/09/22/a-chemical-volcano-the-decomposition-of-ammonium-dichromate/#comments</comments>
		<pubDate>Tue, 22 Sep 2009 15:17:33 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Chemical Energetics]]></category>
		<category><![CDATA[Decomposition]]></category>
		<category><![CDATA[Volcano]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=140</guid>
		<description><![CDATA[This question was asked for a Secondary 4 prelim paper, which I find it interesting to share with all Chemistry students. The making of a mini-volcano. Did you know that ammonium dichromate, (NH4)2Cr2O7 when exposed to heat, will decompose to form Nitrogen gas, Water Vapor and a green compound Chromium III oxide, Cr2O3. This reaction [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=140&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>This question was asked for a Secondary 4 prelim paper, which I find it interesting to share with all Chemistry students.</p>
<p>The making of a mini-volcano.</p>
<p>Did you know that ammonium dichromate, <strong>(NH4)2Cr2O7</strong> when exposed to heat, will decompose to form Nitrogen gas, Water Vapor and a green compound Chromium III oxide, Cr2O3.</p>
<p>This reaction is highly exothermic, and gives off orange sparks, throws the green Cr2O3 upwards, mimicking the volcanic-effect.</p>
<p><strong>!!!  Hazards  !!! DO NOT TRY THIS AT HOME. </strong>Ammonium Dichromate causes cancer!</p>
<p>Chromium salts are irritating to the skin and respiratory tracts, and are also carcinogenic.    The best way to do this demonstration is on a large piece of aluminum foil, which can then be used to wrap up the chromium salts produced.</p>
<p><strong>Videos to watch:</strong></p>
<span style="text-align:center; display: block;"><a href="http://cambridgechemistry.wordpress.com/2009/09/22/a-chemical-volcano-the-decomposition-of-ammonium-dichromate/"><img src="http://img.youtube.com/vi/Fy4LLdhjsb8/2.jpg" alt="" /></a></span>
<span style="text-align:center; display: block;"><a href="http://cambridgechemistry.wordpress.com/2009/09/22/a-chemical-volcano-the-decomposition-of-ammonium-dichromate/"><img src="http://img.youtube.com/vi/Ula2NWi3Q34/2.jpg" alt="" /></a></span>
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		<title>What is fractional distillation of petrols?</title>
		<link>http://cambridgechemistry.wordpress.com/2009/08/22/what-is-fractional-distillation-of-petrols/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/08/22/what-is-fractional-distillation-of-petrols/#comments</comments>
		<pubDate>Sat, 22 Aug 2009 15:21:15 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Organic Chemistry]]></category>
		<category><![CDATA[fractional distillation]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=143</guid>
		<description><![CDATA[A very good video (1min 30 sec) to explain how crude oil is separated into its separate fractions by fractional distillation.<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=143&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>A very good video (1min 30 sec) to explain how crude oil is separated into its separate fractions by fractional distillation.</p>
<span style="text-align:center; display: block;"><a href="http://cambridgechemistry.wordpress.com/2009/08/22/what-is-fractional-distillation-of-petrols/"><img src="http://img.youtube.com/vi/26AN1LfbUPc/2.jpg" alt="" /></a></span>
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		<title>Reflux Conditions</title>
		<link>http://cambridgechemistry.wordpress.com/2009/07/22/reflux-conditions/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/07/22/reflux-conditions/#comments</comments>
		<pubDate>Wed, 22 Jul 2009 15:25:34 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Chemical Kinetics]]></category>
		<category><![CDATA[Organic Chemistry]]></category>
		<category><![CDATA[Experimental techniques]]></category>
		<category><![CDATA[reflux]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=145</guid>
		<description><![CDATA[Many students wonder what &#8220;heat under reflux&#8221; is like in the laboratory. It is something like distillation but it is performed for long hours, sometimes overnight to ensure all the reactants are thoroughly boiled. Watch this short video to have an idea of what reflux conditions are like &#8212; and you will understand why reflux [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=145&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Many students wonder what &#8220;<strong>heat under reflux</strong>&#8221; is like in the laboratory.</p>
<p>It is something like distillation but it is performed for long hours, sometimes overnight to ensure all the reactants are thoroughly boiled.</p>
<p>Watch this short video to have an idea of what reflux conditions are like &#8212; and you will understand why reflux are often considered drastic conditions.</p>
<p>A detailed demonstration (2min):<br />
<span style="text-align:center; display: block;"><a href="http://cambridgechemistry.wordpress.com/2009/07/22/reflux-conditions/"><img src="http://img.youtube.com/vi/3diTdagF-6U/2.jpg" alt="" /></a></span></p>
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		<title>Question of Chemical Equilibria</title>
		<link>http://cambridgechemistry.wordpress.com/2009/05/15/question-of-chemical-equilibria/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/05/15/question-of-chemical-equilibria/#comments</comments>
		<pubDate>Thu, 14 May 2009 16:34:31 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Chemical Equilibrium]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=113</guid>
		<description><![CDATA[Pure hydrogen iodide (HI) is a gas, which at high temperatures, partially dissociates into hydrogen and iodine according to the equation: 2HI (g) &#60; &#8212;- &#62; H2(g) + I2(g) At 500K, the equilibrium constant, Kc, for the dissociation reaction is 6.25 x 10^-3.  Some pure HI is placed into an evacuated 2.0 dm3 glass tube [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=113&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Pure hydrogen iodide (HI) is a gas, which at high temperatures, partially dissociates into hydrogen and iodine according to the equation:</p>
<p><strong>2HI (g) &lt; &#8212;- &gt; H2(g) + I2(g)</strong></p>
<p>At 500K, the equilibrium constant, Kc, for the dissociation reaction is <span style="text-decoration:underline;">6.25 x 10^-3</span>.  Some pure HI is placed into an evacuated 2.0 dm3 glass tube and heated to 500K. In the equilibrium sample, the concentration of I2 is 3.10 x 10^-5 moldm^-3.</p>
<p>ai) Write an <strong>expression for the Kc </strong>for the dissociation of HI.<br />
ii) What are the <strong>concentrations of H2(g) and HI(g)</strong> in this equilibrium mixture at 500K?<br />
iii) How many<strong> moles of HI  must have been placed</strong> into the 2.0dm3 glass tube originally?</p>
<p>b) At 600K, Kc for the dissociation of HI is 1.56&#215;10^-2. <strong>Describe and explain </strong>the appearance of the contents in this glass as it is heated to 600K.</p>
<p>c) Hydrogen chloride at 500K undergoes no significant dissociation into its elements. Any dissociation of hydrogen chloride can be completely ignored. <strong>What is the pressure in a 750cm3 flask</strong> containing <span style="text-decoration:underline;">8.20 x 10^-2</span> mol of pure HCl at 500K?<br />
<span style="color:#0000ff;"><em><br />
<span style="color:#ff00ff;"><strong>Once you have the answers, you can post it here<br />
</strong></span></em></span></p>
<p><span style="color:#ff00ff;"><strong><em>Enjoy!</em></strong></span></p>
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		<title>Question on Thermochemistry</title>
		<link>http://cambridgechemistry.wordpress.com/2009/05/12/question-on-thermochemistry/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/05/12/question-on-thermochemistry/#comments</comments>
		<pubDate>Mon, 11 May 2009 16:31:36 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Chemical Energetics]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=110</guid>
		<description><![CDATA[a) Using zinc chloride, ZnCl2, as an example, define lattice energy. b) Using the data given below as well as relevant data from the Data Booklet, construct a Born-Haber energy level diagram for zinc chloride. Electron affinity of chlorine = -346 kJmol-1 Enthalpy change of atomization of zinc = +131 kJmol-1 Enthalpy change of formation [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=110&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>a) Using zinc chloride, ZnCl2, as an example, <strong>define lattice energy</strong>.</p>
<p>b) Using the data given below as well as relevant data from the Data Booklet, <strong>construct a Born-Haber energy level diagram for zinc chloride.</strong><br />
Electron affinity of chlorine = -346 kJmol-1<br />
Enthalpy change of atomization of zinc = +131 kJmol-1<br />
Enthalpy change of formation of ZnCl2(s) = -451 kJmol-1</p>
<p>Use the energy level diagram to <strong>calculate the lattice energy of zinc chloride</strong></p>
<p>c) How would you expect the melting point of zinc chloride to <span style="text-decoration:underline;">compare</span> with that of zinc bromide?<br />
Explain your reasoning.</p>
<p><span style="color:#000080;"><em>If you have the answer, you can post here<br />
</em></span></p>
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		<title>Mole concept &#8211; for the Year Ones</title>
		<link>http://cambridgechemistry.wordpress.com/2009/03/23/mole-concept-for-the-year-ones/</link>
		<comments>http://cambridgechemistry.wordpress.com/2009/03/23/mole-concept-for-the-year-ones/#comments</comments>
		<pubDate>Sun, 22 Mar 2009 18:39:11 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[Today I started a JC 1 class revising secondary 4 work on mole concept and calculations. For the stronger Chemistry students, this chapter might seem easy to handle, which is a good thing. However, do not be complacent, and always be alert with calculations. It is easy to make careless mistakes and overlook the number [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=100&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Today I started a JC 1 class revising secondary 4 work on mole concept and calculations.</p>
<p>For the stronger Chemistry students, this chapter might seem easy to handle, which is a good thing. However, do not be complacent, and always be alert with calculations.</p>
<p>It is easy to make careless mistakes and overlook the number of  zeroes and decimal place.</p>
<p>Also, the mole reacting ratio can be rather challenging at times.</p>
<p>If you need further help ,please feel free to post a comment here</p>
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		<title>Merry Xmas and a&#8230;..</title>
		<link>http://cambridgechemistry.wordpress.com/2008/12/14/merry-xmas-and-a/</link>
		<comments>http://cambridgechemistry.wordpress.com/2008/12/14/merry-xmas-and-a/#comments</comments>
		<pubDate>Sun, 14 Dec 2008 13:41:08 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

		<guid isPermaLink="false">http://cambridgechemistry.wordpress.com/?p=86</guid>
		<description><![CDATA[&#8216;Tis the season to be jolly, falalalalalala.. MERRY CHRISTMAS BOYS AND GIRLS To those who have graduated, congratulations! You have made it! For those embarking the journey in Chemistry or in the midst, hope you are enjoying the journey thus far, or at least have a better appreciation of Chemistry. It is always good to [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=86&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>&#8216;Tis the season to be jolly, falalalalalala..<br />
MERRY CHRISTMAS BOYS AND GIRLS <img src='http://s0.wp.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
<p>To those who have graduated, congratulations! You have made it!</p>
<p>For those embarking the journey in Chemistry or in the midst, hope you are enjoying the journey thus far, or at least have a better appreciation of Chemistry.</p>
<p>It is always good to start early, so remember to START DOING YOUR SCHOOL HOLIDAY HOMEWORK! hahaha.</p>
<p>Let me know if you need any clarification or assistance.</p>
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		<title>Titration between acids / bases</title>
		<link>http://cambridgechemistry.wordpress.com/2008/10/30/titration-between-acids-bases/</link>
		<comments>http://cambridgechemistry.wordpress.com/2008/10/30/titration-between-acids-bases/#comments</comments>
		<pubDate>Wed, 29 Oct 2008 21:31:09 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Ionic Equilibrium]]></category>

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		<description><![CDATA[Equivalence point or end-point (when equivalence volume is added such that no more acids nor bases are left, only left with salt) SALT can be classified as 1) NEUTRAL (usually between strong acids and strong bases. pH = 7, due to hydration only) 2) ACIDIC (usually between strong acids and weak bases. pH &#60; 7 [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=66&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Equivalence point or end-point (when equivalence volume is added such that no more acids nor bases are left, only left with salt)</p>
<p>SALT can be classified as<br />
1) NEUTRAL (usually between strong acids and strong bases. pH = 7, due to hydration only)<br />
2) ACIDIC (usually between strong acids and weak bases. pH &lt; 7 due to conjugate acid of weak base)<br />
3) BASIC  (usually between weak acids and strong bases. pH &gt; 7 due to conjugate base of weak acid) </p>
<p>If a base is weak, i.e. undergoes partial ionisation; then its conjugate acid also undergoes partial ionisation. Therefore, a weak base has its own Kb value, and thus its conjugate acid will have its own Ka value ( where Ka = Kw/Kb)</p>
<p>Reverse is true for weak acids and its conjugate bases.</p>
<p>In general, for any substance that behaves as a weak acid (recall, Lowry-Brosted theory states that acid donates H+), to calculate pH, <br />
- [H+] = sq. root (Ka.[acid])<br />
-pH = -lg [H+]</p>
<p>In general, for any substance that behaves as a weak base (recall, Lowry-Brosted theory states that base accepts H+), to calculate pH, <br />
- [OH-] = sq. root (Kb.[base])<br />
-pOH = -lg [OH-]<br />
-pH = 14 &#8211; pOH</p>
<p>Thus a salt can behave as a weak acid or a weak base depending on whether it can accepts or donates H+</p>
<p>Hope this helps !</p>
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		<title>Organic tips</title>
		<link>http://cambridgechemistry.wordpress.com/2008/10/30/organic-tips/</link>
		<comments>http://cambridgechemistry.wordpress.com/2008/10/30/organic-tips/#comments</comments>
		<pubDate>Wed, 29 Oct 2008 21:23:20 +0000</pubDate>
		<dc:creator>cambridgechemistry</dc:creator>
				<category><![CDATA[Aromatic Compounds]]></category>
		<category><![CDATA[Mechanisms]]></category>

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		<description><![CDATA[Just a quick tip:  This is for the electrophilic substitution/ bromination for Phenols and Phenylamines. 1) Br2 (g) in CCl4 &#8212;-&#62; mono-substituted phenol/phenylamine 2) Br2 (l)              &#8212;&#8211;&#62; di-substituted phenol/phenylamine 3) Br2 (ag)           &#8212;&#8212;&#62; tri-substituted phenol/phenylamine Another quick revision tip: Metal-acid reaction is also a [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=cambridgechemistry.wordpress.com&amp;blog=4089614&amp;post=64&amp;subd=cambridgechemistry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Just a quick tip: </p>
<p>This is for the electrophilic substitution/ bromination for Phenols and Phenylamines.</p>
<p>1) Br2 (g) in CCl4 &#8212;-&gt; mono-substituted phenol/phenylamine<br />
2) Br2 (l)              &#8212;&#8211;&gt; di-substituted phenol/phenylamine<br />
3) Br2 (ag)           &#8212;&#8212;&gt; tri-substituted phenol/phenylamine</p>
<p>Another quick revision tip:</p>
<p>Metal-acid reaction is also a reduction/oxidation process</p>
<p>Please remember that in Nucleophilic addition, a racemic mixture is most likely to be formed, unless the reaction is performed naturally by enzymes in living organisms</p>
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